Typescript eslint no unsafe assignment unsafe assignment of an any value - JavaScript

To fix this error, you need to ensure that you are not assigning a value of type any to a variable without first performing a type check or type assertion. In TypeScript, the any type is a type that represents any value and allows you to bypass the type checking process. However, this can lead to runtime errors if you try to access properties or methods that do not exist on the any type.

Here are some ways you can fix this error:

Use a type assertion to explicitly tell the compiler that you are aware of the type of the value being assigned. You can do this by adding an exclamation mark (!) after the value being assigned, like this:

const x: number = someValue as number;

Perform a type check before assigning the value. You can use the typeof operator to check the type of the value being assigned and ensure that it is compatible with the type of the variable being assigned to. For example:
```
if (typeof someValue === 'number') {
const x: number = someValue;
} else {
// handle the case where someValue is not a number
}
```

Use a type guard function to check the type of the value being assigned. A type guard function is a function that returns a boolean value indicating whether a value is of a certain type. You can use a type guard function to narrow the type of a value and ensure that it is compatible with the type of the variable being assigned to. For example:

function isNumber(x: any): x is number {
return typeof x === 'number';
}

if (isNumber(someValue)) {
const x: number = someValue;
} else {
// handle the case where someValue is not a number
}

By using one of these approaches, you can ensure that you are not assigning an unsafe value to a variable and avoid the unsafe assignment error.

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Typescript eslint no unsafe assignment unsafe assignment of an any value – JavaScript